TS EAMCET 11-Sep-2020 Shift 1 Solved Paper

Acceleration of the particle is given as
f=f0(1−‌

t

T

)....(i)
∴ Velocity of particle is given as,
Given that, at t=0,v=0
Hence, from Eq. (i), we get
0=f0(0−0)+c⇒c=0
∴ From Eq. (ii), we have
v=f0(t−‌

t2

2T

)...(iii)
Suppose, acceleration of the particle becomes zero at time t=t1.
Hence, from Eq. (i),
Hence, velocity of particle at t=t1=T, from Eq. (iii),
v=f0(t1−‌

t12

2T

)