TS EAMCET 11-Sep-2020 Shift 1 Solved Paper

Section: Mathematics

© examsiri.com

Question : 80 of 160

Marks: +1, -0

The general solution of the differential equation (1+y2)dx=(Tan−1y−x)dy is

x=(Tan−1y)−1+Ce−Tan−1y
x=(Tan−1y)−1+CeTan−1y
x=(Tan−1y)−1+C
x=(Tan−1y)+1+Ce−Tan−1y

Go to Question:

Prev Question

Next Question