\int{25x^2+8}/\sqrt{25x^2+9}dx=

Correct Answer is : x2√25x2+9+710Sinh−1(5x3)+C

x/2\sqrt{25x^2+9}+\frac{11}{10}Sinh^{-1}({5x}/3)+C

x/2\sqrt{25x^2+9}-7/{10}\log({5x+\sqrt{25x^2+9}/3)+C

x/2\sqrt{25x^2+9}+7/{10}Sinh^{-1}({5x}/3)+C

x/2\sqrt{25x^2+9}+\frac{11}{10}\log({5x-\sqrt{25x^2+9}/3)+C

TS EAMCET 11-Sep-2020 Shift 1 Solved Paper

Section: Mathematics

Question : 72 of 160

Marks: +1, -0

∫

25x2+8

√25x2+9

dx=

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