The equation of the plane passing through the line of intersection of planes \pi_1=2x+6y+4z-7=0, \pi_2=x-y-2z-2=0 and perpendicular to the plane x+y+2z-5=0 is

Correct Answer is : 6x+2y−4z−15=0

TS EAMCET 11-Sep-2020 Shift 1 Solved Paper

Section: Mathematics

Question : 61 of 160

Marks: +1, -0

The equation of the plane passing through the line of intersection of planes π1=2x+6y+4z−7=0,π2=x−y−2z−2=0 and perpendicular to the plane x+y+2z−5=0 is

3x+y−2z=0
6x+2y−4z+55=0
6x+2y−4z−15=0
3x+y−2z−15=0

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