If [\table2,1,1;0,3,-1;1,-1,1] [\table x;y;z]=[\table1;1;0], then [\table x;y;z] =

Correct Answer is : [10−1]+K[−213],K∊ℝ

[\table1;1;0]+\K[\table3;1;-2],\K∊\mathbb{R}

[\table1;1;0]+\K[\table1;-2;3],\K∊\mathbb{R}

[\table1;1;0]+\K[\table-2;1;3],\K∊\mathbb{R}

[\table1;0;-1]+\K[\table-2;1;3],\K∊\mathbb{R}

TS EAMCET 11-Sep-2020 Shift 1 Solved Paper

Section: Mathematics

Question : 6 of 160

Marks: +1, -0

If [

] [

]=[

], then [

Go to Question:

Prev Question

Next Question