TS EAMCET 11-Sep-2020 Shift 1 Solved Paper

It is given that the circles
x2+y2−2x−2y+k=0
and ‌‌x2+y2+4x+6y+4=0
Touches each other externally, so
c1c2=r1+r2
Where, c1(1,1),c2(−2,−3) and r1=√2−k,r2=3
So, ‌‌√9+16=√2−k+3
√9+16=√2−k+3
The point of contact P of two circles, divides the line joining centres c1 and c2 in the ratio r1:r2.