TS EAMCET 11-Sep-2020 Shift 1 Solved Paper

The third side of the isosceles triangle is parallel to the angle bisector of the given lines 7x−y+3=0 and x+y−3=0
Now, the equation of angle bisectors are
‌

7x−y+3

√50

=±‌

x+y−3

√2

⇒‌‌7x−y+3=±5(x+y−3)
or 2x−6y+18=0 and 12x+4y−12=0
or x−3y+9=0 and 3x+y−3=0
Therefore, possible equation of third side passes through point (2,−5) are
x−3y=17 or 3x+y=1