TS EAMCET 11-Sep-2020 Shift 1 Solved Paper

It is given that p and q are roots of quadratic equation x2+7x+3=0
To find the quadratic equation whose roots are
‌

3p

1−2p

and ‌

3q

1−2q

, put ‌

3p

1−2p

=x
3p=x−2px⇒p=‌

x

3+2x

∵p is the root of equation x2+7x+3=0, so
(‌

x

3+2x

)2+7(‌

x

3+2x

)+3=0
So, on comparing with lx2+mx+n=0, we get
l=9,m=19 and n=9
∴‌‌l−m+n=9−19+9=−1