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TS EAMCET 11 May 2024 Shift 2 Solved Paper

Section: Mathematics
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Question : 23 of 160
 
Marks: +1, -0
If 0<B<A<‌
Ï€
4
,cos2B−sin‌2A=‌
√3+1
4√2
 and 2‌cos‌A‌cos‌B=‌
1+√2+√3
2√2
, then cos2‌
4B
3
−sin‌2‌
4A
5
=
[TG EAPCET 11 May 2024 Shift 2]
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