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Question : 9 of 160
Marks:
+1,
-0
Solution:
‌amp(‌)=‌‌⇒amp(2z−i)−amp(z+2i)=‌‌⇒amp[2x+i(2y−1)]−amp[x+i(y+2)]=‌‌⇒tan−1(‌)−tan−1(‌)=tan−11‌⇒tan−1(‌)=tan−11+tan−1(‌)‌⇒tan−1(‌)=tan−1‌‌⇒‌‌‌=‌‌⇒(2y−1)(x−y−2)=2x(x+y+2)‌⇒2xy−2y2−4y−x+y+2=2x2+2xy+4x‌⇒2x2+2y2+5x+3y−2=0,(x,y)≠(0,−2).
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