TS EAMCET 11 May 2024 Shift 1 Solved Paper

Section: Physics

Question : 83 of 160

Marks: +1, -0

The position x (in metre) of a particle moving along a straight line is given by x=t3−12t+3, where ' 't' is time (in second). The acceleration of the particle when its velocity becomes 15ms−1 is

[TG EAPCET 11 May 2024 Shift 1]

15ms−2
24ms−2
18ms−2
12ms−2

Validate

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