\int {d x}/{(x+1) \sqrt{x^2+4}}= [TG EAPCET 11 May 2024 Shift 1]

Correct Answer is : −1√5Sinh−1(4−x2(x+1))+c

\frac{1}{2} \sqrt{\frac{x+1}{x+2}}+c

- {1}/{\sqrt{5}} {\Sinh}^{-1} (\frac{4-x}{2(x+1)}) +c

- {1}/{\sqrt{5}} {\Cosh}^{-1} (\frac{4+x}{2(x-1)}) +c

TS EAMCET 11 May 2024 Shift 1 Solved Paper

Section: Mathematics

Question : 74 of 160

Marks: +1, -0

∫‌

(x+1)√x2+4

[TG EAPCET 11 May 2024 Shift 1]

Go to Question:

Prev Question

Next Question