If y=\sqrt{ \sin (\log 2 x)+\sqrt{ \sin (\log 2 x)+{\sqrt{ \sin (\log 2 x)+. . . \infty}}}, then \frac{d y}{d x}= [TG EAPCET 11 May 2024 Shift 1]

Correct Answer is : cos(log2x)x(2y−1)

\frac{\cos (\log 2 x)}{2 x(2 y-1)}

\frac{\cos (\log 2 x)}{(2 y-1)}

\frac{\cos (\log 2 x)}{x(2 y-1)}

\frac{ \sin (\log 2 x)}{x(2 y-1)}

TS EAMCET 11 May 2024 Shift 1 Solved Paper

Section: Mathematics

Question : 64 of 160

Marks: +1, -0

If y=√sin‌(log‌2‌x)+√sin‌(log‌2‌x)+√sin‌(log‌2‌x)+...∞, then ‌

[TG EAPCET 11 May 2024 Shift 1]

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