TS EAMCET 10-Sep-2020 Shift 2 Solved Paper

We know that the equation of two straight lines which passes through a point (x1,y1) and made a given angle α with the given straight line
y=mx+c are y−y1=‌

m±tan‌α

1∓m‌tan‌α

(x−x1)
Here, x1=1,y1=1,α=60∘
andm=−1 (slope of line x+y−3=0 )
So, equation of lines are
y−1=‌

−1−tan‌60∘

1+(−1)‌tan‌60∘

(x−1)
and ‌‌y−1=‌

−1+tan‌60∘

1−(−1)‌tan‌60∘

(x−1)
⇒‌‌y−1=‌

−1−√3

1−√3

(x−1)
and ‌‌y−1=‌

−1+√3

1+√3

(x−1)
⇒‌‌(y−1)(1−√3)=(−1−√3)(x−1)
and (y−1)(1+√3)=(−1+√3)(x−1) ⇒‌‌(1+√3)x+(1−√3)y−1+√3−1−√3=0
and (1−√3)x+(1+√3)y−1−√3−1+√3=0
⇒‌‌(1+√3)x+(1−√3)y−2=0
and (1+√3)x+(1−√3)y−2=0