TS EAMCET 10-Sep-2020 Shift 2 Solved Paper

Section: Mathematics

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Question : 20 of 160

Marks: +1, -0

Let a be maximum value of (3‌cos‌θ−4‌sin‌θ) and θ≠‌

nπ

2

. If α=asin2θ⋅cos3θ and β=asin3θ⋅cos2θ, then √‌

(α2+β2)5

(αβ)4

=

5sin
θ
2
cos2
θ
2
−3sinθ
5
16

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