TS EAMCET 10-Sep-2020 Shift 2 Solved Paper

Given, word ATRAPATRAM
Here, A→4 times
T→2 times
R→2 times
P→1 time
M→1 time
(i) All A's are together,
Then it will be consider as one letter and remaining 6 letters and 1′A′s (including 4A′s )will be consider as 7 letters.
∴ Number of arrangement =‌

7!

2!2!

=x . . . (i)
(ii) no two A′ s are together.
such that −T−R−P−T−R−M−
∴ Number of arrangement =‌7C4×‌

6!

2!2!

=y‌‌...(ii)
∴‌‌x+y‌‌=‌

7!

2!2!

+‌7C4×‌

6!

2!2!

‌‌=‌

7×6!

2!2!

+‌7C3×‌

6!

2!2!

=‌

6!

2!2!

(7+‌7C3)
‌‌=‌

6!

2!2!

(7+35)=‌

6!

2!2!

(42)