TS EAMCET 10-Sep-2020 Shift 2 Solved Paper

Given,
In k=5.0−‌

12000

T

Also, ∵‌‌ In k=log‌A−‌

Ea

RT

and k=Ae−Ea∕RT
or, ‌‌logℓK=logℓA=‌

Ea

RT

where, A= pre-exponential constant
i.e. frequency factor
Ea= activation energy
R‌‌=‌ gas constant ‌=2kcalmol−1
Tk‌‌=‌ temperature ‌
k‌‌=‌ rate constant ‌
Thus, ‌

Ea

RT

=‌

12000

T

or Ea=12000×R
∴ Ea=‌

12000×2

1000

‌‌( in kcalmol−1)
i.e. ‌‌Ea=24kcalmol−1
Hence, option (a) is the correct answer.