TS EAMCET 10-Sep-2020 Shift 2 Solved Paper

∵ Concentration of NaOH(N1)=0.1N
Volume of NaOH used (V1)=25mL
Concentration of HCl(N2)=0.1N
Volume of HCl(V2) used =V2 and ‌‌N1V1=N2V2
Thus, V2=‌

N1V1

N2

=‌

0.1×25

0.1

Volume of HCl used (V2)=25mL=V1
Thus, to convert 500mLHCl solution to 0.1NHCl,
we need 500mL of water.
Hence, option (b) is the correct answer.