TS EAMCET 10-Sep-2020 Shift 2 Solved Paper

Given,
Ionic product of Ca(OH)2=5.5×10−6
Concentration of NaOH solution =010M
∴Ionic product of Ca(OH)2=5.5×10−6
or, Ca(OH)2=[Ca2+]+2[OH−]
Let, solubility =S
Ca2++2[OH−]\S‌‌(2S)2
Also, K‌sp ‌=4S3
where, Ksp= solubility product
∴ Due to common ion effect,
Molar solubility of Ca(OH)2=‌

5.5×10−6

0.1×0.i

=5.5×10−4
Hence, option (c) is the correct answer.