TS EAMCET 10-Sep-2020 Shift 2 Solved Paper

∵ In acidic medium, KMnO4, i.e. MnO4−
changes to Mn2+ as follows:
MnO4−+8H++5e−⟶Mn2++4H2O
Hence, equivalent weight =‌

158

5

(Given, molecular weight of KMnO4=158g and5 electrons are used)
∴‌‌‌

158

5

=31.6g
Hence, option (c) is the correct answer.