TS EAMCET 10-Sep-2020 Shift 1 Solved Paper

The motion of two car A and B is shown in the figure.
Relative velocity of car A w.r.t. carB is
vAB=vA−vB=15−10=5m/sDistance to be covered for overtake is given as
s=4m+4m=8m
Time taken by cars to cross = Distance\/Speed
=‌

s

VAB

=‌

8

5

=1.6s