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Question : 76 of 160
Marks:
+1,
-0
Solution:
Let
I=‌| 3dx |
| 1+e√8‌sin(x−‌) |
....(i)
=‌| 3dx |
| 1+e√8‌sin(‌+‌−x−‌) |
[f(x)dx=f(a+b−x)dx] =‌| 3e√8‌sin(x−) |
| e√8‌sin(x−‌)+1 |
...(ii)
On adding Eq. (i) and Eq. (ii), we get
∴‌‌I=‌
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