\int{y^3+\sqrt^{3}{y^4}+\sqrt^6{y^2}}/{y(1+\sqrt^3{y^2})}dy=

Correct Answer is : 343√y4+Tan−1(3√y)+C

{3/4}\sqrt^3{y^4}+\Tan^{-1}(\sqrt^3{y})+C

3/2y^{2/3}+6\,\Tan^{-1}(\sqrt^6{y^2})+C

2/{3\sqrt^3y^2}+6\log(1+y^2)+\C

3/{1+y}+\Tan^{-1}(\sqrt^3{y^2})+\C

TS EAMCET 10-Sep-2020 Shift 1 Solved Paper

Section: Mathematics

Question : 71 of 160

Marks: +1, -0

∫

y3+3√y4+6√y2

y(1+3√y2)

dy=

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