TS EAMCET 10-Sep-2020 Shift 1 Solved Paper

We have
2x+py+6z=8
x+2y+qz=5
x+y+3z=4
Now, if we express above equation in matrix form, We have,
AX=B
Where, For no solution |A|=0
For no solution |A|=0
⇒|

2	p	6
1	2	q
1	1	3

|=0
⇒3p+2q−pq−6=0
⇒3p−6+2q−pq=0
⇒3(p−2)−q(p−2)=0
⇒(p−2)(3−q)=0⇒p=2,3
But for p=2 equations 2x+py+6z=8 and x+y+3z=4 are same.
So, p≠2,q=3