Let OA^{-}=a^{-}, OB^{-}=b^{-} be two non collinear vectors, OP^{-}=x_1a^{-}+y_1b^{-}, OQ^{-}=x_2a^{-}+y_2b^{-} and \stackrel{-}{A^'O}=\stackrel{-}{OA}, \stackrel{-}{B^'O}=\stackrel{-}{OB}. If x_1=-3/4, x_2=1/3, y_1=7/4, y_2=5/3, then

Correct Answer is : P lies on the Δ A'OB and O lies outside the Δ AOB

P lies inside the Δ A'OB and Q lies outside the Δ AOB

P lies outside the Δ AOB' and Q lies on the Δ A'OB'

P lies inside the Δ AOB and O lies outside the Δ AOB'

P lies on the Δ A'OB and O lies outside the Δ AOB

TS EAMCET 10-Sep-2020 Shift 1 Solved Paper

Section: Mathematics

Question : 29 of 160

Marks: +1, -0

Let O

−

be two non collinear vectors, O

−

=x1

−

+y1

−

, O

−

=x2

−

+y2

−

and

−

A′O

−

B′O

−

. If x1=−

,x2=

,y1=

,y2=

, then

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