TS EAMCET 10 May 2024 Shift 1 Solved Paper

Section: Mathematics

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Question : 6 of 160

Marks: +1, -0

If a≠b≠c,∆1=|

1	a2	bc
1	b2	ca
1	c2	ab

|,∆2=|

1	1	1
a2	b2	c2
a3	b3	c3

| and ‌

∆1

∆2

=‌

6

11

, then 11(a+b+c)=

[TG EAPCET 10 May 2024 Shift 1]

0
1
ab+bc+ca
6(ab+bc+ca)

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