TS EAMCET 04 May 2019 Shift 2 Solved Paper

Section: Mathematics

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Question : 65 of 160

Marks: +1, -0

If t is a parameter and x = t +

1

t

, y = t -

1

t

, then

d2y

dx2

=

4t
(t2+1)2
t2
t2+1
4t3
(t2+1)3
−4t3
(t2−1)3

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