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Question : 62 of 160
Marks:
+1,
-0
Solution:
Consider the limit
[log(1+‌)−log‌] It is solved as,
[log(1+‌)−log‌]‌‌=[log(‌)] ‌‌=x[log(‌+1)] ‌‌=[‌] ‌‌=[‌] Solve further
[log(1+‌)−log‌]‌‌=[‌] ‌‌=‌ ‌‌=2
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