If A + B + C = \pi/3 , then sin ({\pi-6A}/6) + sin ({\pi-6B}/6) + sin C =

Correct Answer is : 4 cos (π−6A12) cos (π−6B12) sin C2

- 1 + 4 cos (\frac{\pi-6A}{12}) cos (\frac{\pi-6B}{12}) \sin C/2

4 sin (\frac{\pi+6A}{12}) sin (\frac{\pi+6B}{12}) cos C/2

1 - 4 cos (\frac{\pi-6A}{12}) cos (\frac{\pi-6B}{12}) cos \frac{\pi-6C}{12}

4 cos (\frac{\pi-6A}{12}) cos (\frac{\pi-6B}{12}) sin C/2

TS EAMCET 04 May 2019 Shift 2 Solved Paper

Section: Mathematics

Question : 22 of 160

Marks: +1, -0

If A + B + C =

, then sin (

π−6A

) + sin (

π−6B

) + sin C =

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