TS EAMCET 04 May 2019 Shift 2 Solved Paper

Consider the reaction shown below,
H2SO4⇌2H++SO42−
The concentration of H+ is calculated as
H+‌‌=2×0.001M
‌‌=0.002M
The pH is calculated as,
pH‌‌=−log[H+]
‌‌=−log(0.002)
‌‌=2.69
The pOH is calculated as
pH+pOH=14
pOH=14−pH
pOH=14−2.69
pOH=11.31
The [OH] concentration is calculated as,
pOH‌‌=−log[OH−]
11.31‌‌=−log[OH−]
[OH−]‌‌=5×10−12