TS EAMCET 04 May 2019 Shift 2 Solved Paper

Potential difference between the centre of the rod and one end of the rod due to revolution in magnetic is given by,
V′‌‌=Bπr2f
‌‌=0.5π(40cm×‌

10−2m

1cm

)2(10‌rev∕s)
‌‌=0.8π
Potential difference between two ends of rod due to revolution in the magnetic field is given by,
V‌‌=2V′
‌‌=2(0.8π)
‌‌=1.6πV