TS EAMCET 04 May 2019 Shift 2 Solved Paper

The resistance of a resistor is calculated as,
Rt=R0(1+αt)
Resistance of resistor at temperature t1=40∘C is given by
Rt1‌‌=R0(1+αt1)
100‌‌=R0(1+(2×10−4×40))
R0‌‌=‌

100

1.008

‌‌=99.21Ω
Now, the current drops to 0.098A at temperature t2
Rt2‌‌=‌

V

I

‌‌=‌

10

0.098

‌‌=102.04Ω
Resistance of resistor at temperature t2 is given by,
Rt2=R0(1+αt2)
102.04‌‌=99.21(1+(2×10−4t2))
t2‌‌=‌

0.0285

2×10−4

‌‌=142∘C