TS EAMCET 04 May 2019 Shift 2 Solved Paper

Consider the ray diagram shown below.
The lens formula is given by,
‌

1

f

=‌

1

v

−‌

1

u

Substitute −3cm for u and 2cm for f in equation (I).
‌

1

f

=‌

1

v

−‌

1

u

‌

1

v1

=‌

1

2

−‌

1

3

‌

1

v1

=‌

3−2

6

v1=6cm
For lens B
u2=−(14−6)
=−8cm
‌ So, ‌
‌

1

v2

−‌

1

u2

‌‌=‌

1

f2

‌

1

v2

+‌

1

8

‌‌=‌

1

5

v2‌‌=‌

40

8−5

v2‌‌=‌

40

3

cm
Therefore, the distance of final image (A′′B′′) from lens A is,
D‌‌=14+v2
‌‌=(14+‌

40

3

)cm
‌‌=‌

82

3

cm