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Question : 10 of 160
Marks:
+1,
-0
Solution:
Consider the expression
(sin‌+i‌cos‌) The above expression is solved as,
(sin‌+i‌cos‌)‌‌=i‌(sin‌+−i‌sin‌) ‌‌=i‌e−‌ ‌‌=i‌kr ‌‌=i[k(‌)] Solve further
(sin‌+i‌cos‌)‌‌=i(‌) ‌‌=i‌ ‌‌=−i
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