TS EAMCET 04 May 2019 Shift 1 Solved Paper

Consider the below diagram. Let assume the time of the collision of two particle be t
The equation of the motion is given by,
s=ut+‌

1

2

at2
For particle A the above equation is written as
30‌‌=(0)t+‌

a‌cos‌60∘‌t2

2

30‌‌=‌

0.4

2

×‌

1

2

×t2
t‌‌=√300s
This implies that the both particle travel equal distance in horizontal direction in t=√300s
The speed at the time of collision is calculated as
u‌‌=‌

1

2

×0.4×‌

√3

2

×√300
‌‌=3m∕s