If the position vectors of the points A , B , C , D given by \overline{i}+2 \overline{j}+3 \overline{k}, 2 \overline{i}-\overline{j}+2 \overline{k}, \frac{1}{4}(7 \overline{i}+15 \overline{j}+15 \overline{k}) and \frac{1}{3}[7 \overline{i}+2 \overline{j}+(5+3 a) \overline{k}] respectively are such that |\overline{ AC }|=|\overline{ BD }|, then 16(3 a-1)^{2}=

TS EAMCET 04 May 2019 Shift 1 Solved Paper

Section: Mathematics

Question : 29 of 160

Marks: +1, -0

If the position vectors of the points A,B,C,D given by i+2j+3k,2i−j+2k, ‌

(7i+15j+15k) and ‌

[7i+2j+(5+3a)k] respectively are such that |AC|=|BD|, then 16(3a−1)2=

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