TS EAMCET 04 May 2019 Shift 1 Solved Paper

For the case I
The 4 questions are from first 5 questions and 6 questions are from remaining 8 questions so,
5C4×8C6‌‌=5×28
‌‌=140
For the case II
The 5 questions are from first 5 questions and the other 5 questions are from the remaining 8 question so,
5C5×8C5‌‌=1×56
‌‌=56
Therefore, the total number of ways are,
140+56=196