TS EAMCET 04 May 2019 Shift 1 Solved Paper

The expression which gives the relation between the voltage and current is given by,
V=IR
For the potential drop of 2V takes place across the parallel branch AB the expression is calculated as,
V=IR
2=I32
I3=1A
The voltage across the branch AB is calculated as,
VAB‌‌=5−I3R2
2‌‌=5−1×R2
R2‌‌=3Ω
The voltage V2 across R2 is calculated as,
v2=−I3R2
=−3×1
=−3V