TS EAMCET 03 May 2019 Shift 2 Solved Paper

The expression for the Poisson’s ratio is given by,
σ=‌

‌ Lateral strain ‌

‌ Longitudenal strain ‌

Thus,
σ=−‌

‌ ∆D D

∆L L

..............(1)
since
A=πD2
‌

∆A

A

=2‌

∆D

D

................(2)
From equations (1) and (2)
‌

∆A

A

=2σ‌

∆L

L

...............(3)
The expression for Young's modulus is given by,
Y=‌

FL

A∆L

................(4)
From equation (3) and (4)
‌

∆A

A

‌‌=‌

2×0.32×22

1.1×1011×10−6

‌‌=12.8×10−5
Calculate the value of ‌

∆A

A

%
‌

∆A

A

%‌‌=12.8×10−3
‌‌=12.6×10−3