The solution of the differential equation (1+y^2) + (x-e^{\tan^{-1}y})\frac{dy}{dx} = 0 is

Correct Answer is : 2xetan−1y−e2tan−1y = c

xe^{2tan^{-1}y}-e^{\tan^{-1}y} = c

2xe^{\tan^{-1}y}-e^{2tan^{-1}y} = c

xe^{\tan^{-1}y}+2e^{2tan^{-1}y} = c

TS EAMCET 03 May 2019 Shift 2 Solved Paper

Section: Mathematics

Question : 80 of 160

Marks: +1, -0

The solution of the differential equation (1+y2) + (x−etan−1y)

= 0 is

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