TS EAMCET 03 May 2019 Shift 2 Solved Paper

Section: Mathematics

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Question : 8 of 160

Marks: +1, -0

If the point (

k−1

k

,

k−2

k

) lies on the locus of z satisfying the inequality |

z+3i

3z+i

| < 1, then the interval in which k lies is

(- ∞ , 2) ∪ (3 , ∞)
[2 , 3]
[1 , 5]
(- ∞ , 1) ∪ (5 , ∞)

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