TS EAMCET 03 May 2019 Shift 2 Solved Paper

The probability of selection of I and II bag is
P(I)=P(II)=‌

1

2

The probability of selection of red ball from first bag
P(‌

R

I

)=‌

3

7

The probability of selection of red ball from the second bag
P(‌

R

Π

)=‌

5

11

The required probability is

P(‌

II

R

)=‌‌‌

P(II)×P( II R )

P(I)×P(‌ R I )+P(II)×P(‌ II R )

‌‌=‌

‌ 1 2 × 5 11

1 2 ×‌ 3 7 +‌ 1 2 ×‌ 5 11

=‌‌‌

35

68