TS EAMCET 03 May 2019 Shift 2 Solved Paper

Section: Mathematics

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Question : 2 of 160

Marks: +1, -0

Let f (x) = (x+1)2 - 1 , x ≥ - 1. Then {x|f(x)=f−1(x)} =

{0 , 1 , - 1}
{−1+
−3+i√3
2
,
−3−i√3
2
}
{0 , - 1}
ϕ

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