Correct Answer is : 12+3x16+27x2256

1-\frac{3x}{16}-\frac{15}{256} x^2

1/2+\frac{3x}{16}+\frac{27x^2}{256}

1/2-\frac{3x}{16}+\frac{15}{256} x^2

TS EAMCET 03 May 2019 Shift 2 Solved Paper

Section: Mathematics

Question : 18 of 160

Marks: +1, -0

For |x| <

, the approximate value of

(4−3x)

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