TS EAMCET 03 May 2019 Shift 2 Solved Paper

It is given the solution of NaCl and urea are isotonic.
Therefore, i×CRT(NaCl)=CRT(‌ urea ‌)
Here, the concentration is C, Van't Hoff factor is i gas constant is R and the temperature is T
∴i×C(NaCl)=C(‌ urea ‌)
i×‌

0.1

1L

=‌

wB

mB

×‌

1000

V

i=‌

1.1

60

×‌

1000

100

×‌

1

0.1

=1.83
For ionsiation,
i=1−α+nα
Here, the degree of dissociation is α and the number of particles is n
The number of particle for NaCl is 2
Thus, 1.83‌‌=1+α
α‌‌=0.83