TS EAMCET 03 May 2019 Shift 2 Solved Paper

The combustion of one mole of CH3OH is:
CH3OH+O2→CO+2H2O
The oxidation number of carbon in CH3OH is, x+(3×1)+(1×2)+(1×1)=0
x=−2
The oxidation number of carbon in CO is,
x+(1×−2)=0
x=2
The difference in oxidation number becomes 2−(−2)=4
The expression for equivalent weight of methanol is,
E‌‌=‌

MCH3OH

‌ change in oxidation number ‌

‌‌=‌

32

4

‌‌=8