TS EAMCET 03 May 2019 Shift 1 Solved Paper

Section: Mathematics

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Question : 62 of 160

Marks: +1, -0

lim

x→∞

(

2x2+3x+4

x2−3x+5

)

3|x|+1

2|x|−1

=

3
2
2√2
3
√2

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