TS EAMCET 03 May 2019 Shift 1 Solved Paper

Section: Mathematics

Question : 58 of 160

Marks: +1, -0

If e1 is the eccentricity of the ellipse

= 1 and e2 is the eccentricity of a hyperbola passing through the foci of the given ellipse and e1e2 = 1, then the equation of such a hyperbola among the following is

x2
9
−
y2
16
= 1
y2
9
−
x2
16
= 1
x2
9
−
y2
25
= 1
x2
25
−
y2
9
= 1

Validate

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