If α 1 = -1 then find α 2 ,α 3 in \alpha _{n} = \:\frac{\alpha _{n−1}}{n + 2},\:n > 1\:\forall\:n \in N

Correct Answer is : \;{−1}/{4},\;{−1}/{20}

TNPSC Group 4 General Knowledge 2019 Paper

Question : 98 of 100

Marks: +1, -0

If α₁ = -1 then find α₂,α₃ in $α _{n} = \:\;{α\;_{n−1}}/{n\;+\;2},\:n > 1\:∀\:n ∈ N$

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