The value of : \frac{x^{3}−1}{x + 3} \div \frac{x^{2} + x + 1}{3x + 9} = ?

TNPSC Group 2 2017 Paper

Question : 66 of 100

Marks: +1, -0

The value of :

\;{x^{3}−1}/{x\;+\;3} ÷ \;{x^{2}\;+\;x\;+\;1}/{3x\;+\;9}

= ?

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